196x^2-196x-739=0

Solution for 196x^2-196x-739=0 equation:

196x^2-196x-739=0

a = 196; b = -196; c = -739;
Δ = b2-4ac
Δ = -1962-4·196·(-739)
Δ = 617792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{617792}=\sqrt{3136*197}=\sqrt{3136}*\sqrt{197}=56\sqrt{197}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-56\sqrt{197}}{2*196}=\frac{196-56\sqrt{197}}{392}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+56\sqrt{197}}{2*196}=\frac{196+56\sqrt{197}}{392}
$